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 Entire forum ➜ SMAUG ➜ SMAUG coding ➜ Making something like capitalize
Making something like capitalize

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Posted by Metsuro   USA  (389 posts)  Bio
Date Fri 26 May 2006 12:31 AM (UTC)
Message
ok well looking at capitalize... I changed it to...

char *capitalize( const char *str )
{
static char strcap[MAX_STRING_LENGTH];
int i;

for( i = 0; str[i] != '\0'; i++ )
strcap[i] = str[i];
strcap[i] = '\0';
strcap[0] = UPPER( strcap[0] );
return strcap;
}

donno if it was smart to remove LOWER( str[i] ) but I did so my strings could have a Capital in the begining and more somewhere else in the string... Now what I want to do, is make something like this to check for periods and the like at the end of the string, and if there isn't a ?, !, or a period, to add a period at the end of the string, but I dont know how to do something like that.
Everything turns around in the end
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Posted by David Haley   USA  (3,881 posts)  Bio
Date Reply #1 on Fri 26 May 2006 01:57 AM (UTC)
Message
Just find the last character -- the one before the \0 -- and check if it's a punctuation mark. If it is, do nothing, if it isn't, change the \0 to a period and add a \0 afterwards.
David Haley aka Ksilyan
Head Programmer,
Legends of the Darkstone

http://david.the-haleys.org
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Posted by Metsuro   USA  (389 posts)  Bio
Date Reply #2 on Fri 26 May 2006 02:56 AM (UTC)
Message
saddly, I have no idea what you said heh.
Everything turns around in the end
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Posted by Zeno   USA  (2,871 posts)  Bio
Date Reply #3 on Fri 26 May 2006 03:04 AM (UTC)
Message
Get the length of the string, then use an ifcheck to check the last character in the string for whatever you need.
Zeno McDohl,
Owner of Bleached InuYasha Galaxy
http://www.biyg.org
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Posted by Metsuro   USA  (389 posts)  Bio
Date Reply #4 on Fri 26 May 2006 03:17 AM (UTC)
Message
I'd like to note, i'm not really good with coding, i just get lucky sometimes, mind giving me an example how I might do that please?
Everything turns around in the end
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Posted by Zeno   USA  (2,871 posts)  Bio
Date Reply #5 on Fri 26 May 2006 03:21 AM (UTC)
Message
I keep thinking to say "string.length()" but that's C++. I think the function is called len to get the length? Check the manual for it.
Zeno McDohl,
Owner of Bleached InuYasha Galaxy
http://www.biyg.org
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Posted by Tzaro   USA  (41 posts)  Bio
Date Reply #6 on Fri 26 May 2006 04:37 AM (UTC)
Message
the function is called "strlen()" :)

Implementer of Lost Prophecy,
Tzaro
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Posted by Metsuro   USA  (389 posts)  Bio
Date Reply #7 on Fri 26 May 2006 09:51 AM (UTC)
Message
Now to find out how to use it...
Everything turns around in the end
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Posted by David Haley   USA  (3,881 posts)  Bio
Date Reply #8 on Fri 26 May 2006 09:53 AM (UTC)
Message
You can type "man strlen" to get the documentation on how the function works.

I have the impression that you're not quite clear on how strings work in C, but before I start explaining it (as it can get lengthy and I'm lazy and don't want to type unless I have to :P) could you confirm that that's the problem?

In short:
A string is a block of memory that contains a sequence of characters, ending at the first character that is equal to '\0' (== 0).
David Haley aka Ksilyan
Head Programmer,
Legends of the Darkstone

http://david.the-haleys.org
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Posted by Metsuro   USA  (389 posts)  Bio
Date Reply #9 on Fri 26 May 2006 10:24 PM (UTC)
Message
Yea, I dont know much about coding in general, but I know how to change things to make them work the way I want, but i dont know what I am actually changing things to, and why =P
Everything turns around in the end
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Posted by Metsuro   USA  (389 posts)  Bio
Date Reply #10 on Sat 27 May 2006 07:54 AM (UTC)
Message
ok so strlen, gives the lenth of a string, but I still dont know how to use that in anyway <.<
Everything turns around in the end
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Posted by David Haley   USA  (3,881 posts)  Bio
Date Reply #11 on Sat 27 May 2006 09:25 AM (UTC)
Message
OK. In C, a string is contained in a block of memory, where a block of memory is just a sequence of bytes. (Everything, in a sense, is contained in a block of memory; an integer is a four-byte block of memory.)

A 'string' (in C, mind you) is defined as the sequence of characters starting at a given point in memory, and continuing up until the first character equal to 0 -- that's numerical 0, not the character '0' (whose numerical value is actually 48).

So, to refer to a string, you carry around a pointer to the block of memory containing the first character of the string.

What strlen does is quite simple. It basically loops over the string, increasing the memory pointer by one character at a time, counting how many characters it finds until it finds a 0. Note that this is basically what Capitalize is doing:
char *capitalize( const char *str )
{
   static char strcap[MAX_STRING_LENGTH];
   int i;

   for( i = 0; str[i] != '\0'; i++ )
      strcap[i] = str[i];
   strcap[i] = '\0';
   strcap[0] = UPPER( strcap[0] );
   return strcap;
}


Look at what this function is doing. It is looping over all characters in 'str', copying them all into the 'strcap' block of memory, until it finds a character in 'str' at address 'i' equal to numerical zero.

If you know that the string is of length l, then the last character is at index l-1. Therefore, using strlen will tell you how long the string is, and you can use that information to get the last character.

Then, you simply need to examine the last character to see if it's a punctuation mark or not.

If it's not punctuation, you need to set index l to a period, and set index l+1 to numerical zero, in order to mark that the string ends one character later.
David Haley aka Ksilyan
Head Programmer,
Legends of the Darkstone

http://david.the-haleys.org
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Posted by Metsuro   USA  (389 posts)  Bio
Date Reply #12 on Sat 27 May 2006 10:52 AM (UTC)
Message
Thanks to you explaining it a little I came up with this...

char *capper( const char *str );
{
int i;
static char temp[MAX_STRING_LENGTH];

i = strlen( str );
if( str[i-1] != '.' )
sprintf( temp, "%s.", capitalize( str ) );
else
sprintf( temp, "%s", capitalize( str ) );
return temp;

}

Not sure if this was the best way to do it... but it comes up with what I want...
Everything turns around in the end
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Posted by Metsuro   USA  (389 posts)  Bio
Date Reply #13 on Sat 27 May 2006 10:58 AM (UTC)
Message
But I cant seem to get it to check for periond, !, and ? all at the same time. I thought you could just do '.' || '!' but that doesn't work soo I am guessing something I've done is incorrect.
Everything turns around in the end
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Posted by Zeno   USA  (2,871 posts)  Bio
Date Reply #14 on Sat 27 May 2006 06:53 PM (UTC)
Message 
if ( str[i-1] != '.' && str[i-1] != '!' && str[i-1] != '?' )

You intend it to be that?
Zeno McDohl,
Owner of Bleached InuYasha Galaxy
http://www.biyg.org
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